Jawaban Ulangan Ulang 3 Logaritma .pdf

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Jawaban Ulangan Ulang 3 Logaritma [Semester Genap]
Tipe Soal Kiri
Soal

Jawaban

1. log 100 + log 0,1 =….

Jawab :
10

2. 9 log 64  8 log 5  25 log 27  ....

log10 2 

10

log 10 1  2  1  1

Jawab :
9

log 64  8 log 5  25 log 27 
32



log 2 6 

23

2
log 5  5 log 33 (kemudian disusun lagi)

 62  13  32  3 log 2  2 log 5  5 log 3
 32 3 log 3



3.

1
3

5

jika log 3  q , maka tentukan nilai log

3
= 1, 5
2

Jawab :
1
45

5
1
3

log 3  q
-1

log 451  3 log(9 x5) 

1 3
1

( log 9  3 log 5)
3
3
  1( 3 log 3 2  3 log 5)   1(2. log 3  log 5)
1
1  2q  1
  1(2  )   2  
q
q
q

Jawab :
2

4. Tentukan penyelesai an dari log(x  2 x  2)  0

10

log(x 2  2 x  2)  0

10 0  x 2  2 x  2
1  x 2  2x  2
0  x 2  2x  3
0  (x - 3)(x  1)

5.

7

1
7

log 3

6

36

x = 3 atau x = -1
ingat a log b  c, syaratnya b  0
maka x2 – 2x -2 harus lebih dari 0.
Saat x =3, maka 32 – 2(3) -2 = 1 (berlaku)
Saat x = (-1), maka (-1)2 – 2(-1) -2 = 1 (berlaku)
Sehingga ada dua jawaban untuk x yang memenuhi yaitu
3 dan -1
Jawab :
log 81

 ....

7

7 1

log 3

6

62

log 81

7

7

log 3

1
1

 31  812
1
9
3
 9 13



6

6

1

log 81 2


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