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2012 . March . 29

Jawaban Ulangan Ulang 3 Logaritma

Jawaban Ulangan Ulang 3 Logaritma.pdf . by Ita Chan

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Jawaban Ulangan Ulang 3 Logaritma [Semester Genap] Tipe Soal Kiri Soal Jawaban 1. log 100 + log 0,1 =…. Jawab : 10 2. 9 log 64  8 log 5  25 log 27  .... log10 2  10 log 10 1  2  1  1 Jawab : 9 log 64  8 log 5  25 log 27  32  log 2 6  23 2 log 5  5 log 33 (kemudian disusun lagi)  62  13  32  3 log 2  2 log 5  5 log 3  32 3 log 3  3. 1 3 5 jika log 3  q , maka tentukan nilai log 3 = 1, 5 2 Jawab : 1 45 5 1 3 log 3  q -1 log 451  3 log(9 x5)  1 3 1 ( log 9  3 log 5) 3 3   1( 3 log 3 2  3 log 5)   1(2. log 3  log 5) 1 1  2q  1   1(2  )   2   q q q Jawab : 2 4. Tentukan penyelesai an dari log(x  2 x  2)  0 10 log(x 2  2 x  2)  0 10 0  x 2  2 x  2 1  x 2  2x  2 0  x 2  2x  3 0  (x - 3)(x  1) 5. 7 1 7 log 3 6 36 x = 3 atau x = -1 ingat a log b  c, syaratnya b  0 maka x2 – 2x -2 harus lebih dari 0. Saat x =3, maka 32 – 2(3) -2 = 1 (berlaku) Saat x = (-1), maka (-1)2 – 2(-1) -2 = 1 (berlaku) Sehingga ada dua jawaban untuk x yang memenuhi yaitu 3 dan -1 Jawab : log 81  .... 7 7 1 log 3 6 62 log 81 7 7 log 3 1 1  31  812 1 9 3  9 13  6 6 1 log 81 2

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Jawaban Ulangan Ulang 3 Logaritma.pdf
Title
Jawaban Ulangan Ulang 3 Logaritma
Author
Ita Chan
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