prad staly 2013 nopass (PDF)
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zorcowych z nalizy
Zadanie
(WS)
Zna
Uo
…
(
RF
R1
=
Ro
Ui
Uo
R2
a)
RF
R1
R2
= 1+
Ro
Ui
Uo
b)
RF
R1
=
R2
Ui1
Dla
Ro
Uo
R3
Ui2
(
=
)
(WS)
Zadanie
R1
R1
Rwe
R2
R2
Rwe
R2
Us
gmUs
gmUs
b)
=
R1
Us
gmUs
Us
a)
=
=
Rwe
=
+
+
=
)
Zadanie
(CS)
12
a)
b)
12
1
2
,
3
,
,
,
i
i
V1
V2
V3
= 22 k = 220
300
Zadanie
=
=
= 250 mV
0
R
(CS)
a)
b)
[ ]
[ ]
[ ]
2
2
U2
U2
4 77 [W],
5 69 [W],
1 14 [W],
[ ]
[ ]
[ ]
3 08 [W],
0 30 [W],
0 73 [W]
[ ]
[ ]
[ ]
4 77 + ( 3 08) + 5 69 + 0 30 + 1 14 + 0 73 = 0 01
0,
8 62 [W],
8 25 [W],
0 126 [W],
[ ]
[ ]
[ ]
0 41 [W],
0 033 [W],
0 201 [W]
8 62 + ( 0 201) + 0 41 + 8 25 + 0 033 + 0 126 =
0 002
0,
=0
=0
R2
Zadanie
a
(WS)
Us
a, b
= ,
=
,
=
,
=
b
Zadanie
(CS)
I2
R
= 8 ,
Zadanie
= 500 mW
(WS/CS)
R5
w
J2
R3
1
= 8 A, = 3 A, = 25 A,
= 250 m ,
= 1 ,
= 500 m ,
= 200 m ,
= 250 m ,
a)
=
a)
Zadanie
[V]
=
[V]
=
J1
J3
R1
R2
[V]
= 1 [V]
R4
= 2 [V]
= 3 [V].
Us
(CS)
2
i
4
Io1
=
Zadanie
1 A,
= A,
= 2 A,
= 1 A,
=
Us
(CS)
)
= 1 V, ( ) = 0 3 A,
= 3 V, ( ) = 2 1 A,
= 4 V, = 1 8 A
2
Io2
= A,
2
)
3
2
= 8 A, = 4 A, = 25 A,
= 250 m ,
= 1 ,
= 500 m ,
= 200 m ,
= 250 m
b)
(
b
2
1, 2 i 3
(
R
a
= A,
= A,
= A
3A
I
Zadanie
UD
Us
(CS)
W obwod
ID
ID=GUD1(UD)
2
-
G=3 S
i
p
2
nina
d
= V,
UD
Us
0 dla < 0
,
1 dla > 0
- < (0)<
(x)
= A
ID
ID=GUD1(UD)
2
G=10 S
2
=
V,
Us
= A
UD
ID
ID=GUD1(UD)
2
G=1 S
2
=
Zadanie
–
w
(CS) =
(WS)
a
s
V,
= 0 A
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