Chap 7 & 8 Online Revision Tutorial (Concise).pdf


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Chapters 7 & 8 ā€“ Online Revision Tutorial (Concise/Moderate/ Detailed)

1.2.2 Problem
P1.

P2.
P3.

The difference equation of a system of a system is
š‘¦š‘¦(š‘›š‘›) = 0.5š‘„š‘„(š‘›š‘›) āˆ’ 0.7š‘„š‘„(š‘›š‘› āˆ’ 1) + 0.2š‘„š‘„(š‘›š‘› āˆ’ 2)
Draw the system block diagram of the system.
Answer

The difference equation of a system of a system is
š‘¦š‘¦(š‘›š‘›) = 0.2š‘„š‘„(š‘›š‘›) + 0.6š‘„š‘„(š‘›š‘› āˆ’ 1) + 0.5š‘¦š‘¦(š‘›š‘› āˆ’ 1) āˆ’ 1.5š‘¦š‘¦(š‘›š‘› āˆ’ 2)
Draw the system block diagram of the system.
Answer
The difference equation of a system of a system is
š‘¦š‘¦(š‘›š‘›) = š‘„š‘„(š‘›š‘›) + 0.5š‘„š‘„(š‘›š‘› āˆ’ 1) āˆ’ 1.2š‘¦š‘¦(š‘›š‘› āˆ’ 1)
Draw the system block diagram of the system.
Answer

1.2.3 Related Past Examination Question
08/09 s2 B3, 07/08 s2 B3

1.3 Answer

1.3.1 Answer of Section 1.1.2
Go back to Problem
P1. š‘¦š‘¦(š‘›š‘›) = 5š‘„š‘„(š‘›š‘›) āˆ’ 2š‘„š‘„(š‘›š‘› āˆ’ 1) + 0.7š‘„š‘„(š‘›š‘› āˆ’ 2)
P2. š‘¦š‘¦(š‘›š‘›) = š‘„š‘„(š‘›š‘›) + 0.5š‘„š‘„(š‘›š‘› āˆ’ 2)
P3. š‘¦š‘¦(š‘›š‘›) = 1.5š‘„š‘„(š‘›š‘›) + 2.3š‘„š‘„(š‘›š‘› āˆ’ 1) + š‘„š‘„(š‘›š‘› āˆ’ 2) + š‘¦š‘¦(š‘›š‘› āˆ’ 1) āˆ’ 0.4š‘¦š‘¦(š‘›š‘› āˆ’ 2)
P4. š‘¦š‘¦(š‘›š‘›) = š‘„š‘„(š‘›š‘›) āˆ’ 0.3š‘„š‘„(š‘›š‘› āˆ’ 1) + 0.6š‘„š‘„(š‘›š‘› āˆ’ 2) āˆ’ 0.1š‘¦š‘¦(š‘›š‘› āˆ’ 2)
1.3.2 Answer of Section 1.2.2
Go back to Problem
P1.
5
Zā€Š-1

āˆ’0.2

Zā€Š-1

0.7

Alternative Answer
5

Zā€Š-1

Zā€Š-1
āˆ’0.2

0.7

5