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30 Points
ECE 519
Homework 1
(Due Thursday, September 1)
Show work and give units to all quantities for full credit.
Print the homework and solve on printed page.
1. When a car has a dead battery, it can be started by connecting the battery
from another car across its terminals as shown below. If the current I = 10A,
which car has the dead battery? How long, in seconds, does it take to charge
the dead battery if it requires 6,000J of energy for charging?
I
+
–
+
–
Car A
12 V
Car B
12 V
Car with the dead battery:
(1 point)
(3 points)
Time to charge the dead battery:
2. For the circuit use KCL to find the branch currents Ia , Ic , Ie , and Ig .
6A
a
h
5A
Ia
c
g
b
Ie
2A
e
d
Ig
4A
f
Ic
Ia =
Ic =
Ie =
(1 point each)
1
Ig =
3. For the circuit use KVL to find the branch voltages Va , Vd , Vg , and Vh .
+
5V f
−
−
+
g
Vg
Vh h
+
−
Va
3V
−
+ a −
+
b
−
c 4V
+
+
Vd d
−
Va =
(1 point each)
+
e 8V
−
Vg =
Vd =
Vh =
4. In the circuit shown determine how much power is absorbed or how much power
is delivered by each circuit element. Find the total power absorbed and total
power delivered. Note: Power is expressed as a positive number.
Ia+
va
a −
Ic
−
c vc
+
Ig−
Element
a
b
c
d
e
f
g
h
vg
g +
Ib−
vb
+
b
Ie
+
e ve
−
+
vd d
−
Id
Ih+
vh
−
h
Voltage (V) Current (A) Power (W)
-6
-8
8
-4
4
8
3
4
7
-14
-7
-10
-1
8
-4
4
−
vf f
+
If
abs/del
(8 points)
Total power absorbed =
(1 point)
Total power delivered =
(1 point)
2
5. Find the current Ia using current divider principle.
30Ω
Ia
4A
80Ω
90Ω
(2 points)
Ia =
6. In the circuit shown below, find the power delivered by the voltage source.
4Ω
4Ω
6Ω
+
50V −
15Ω
24Ω
4Ω
4Ω
Power delivered by the source =
(6 points)
3
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