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x1 is x2 = x3 = x4 = x5 is 0 0 0 0 0 ∼ 0 0 0 0 0 1.0 0 0 0 0 0 1.0 0 0 0 0 0 0 0 1.0 0 0 0 0 0 0 0 0 0 0 free 0 0 0 free Fra dette kan vi se at enhver basis for Nul(P − I5 ) kan skrives som x1 x1 + x5 0 0 β= x0 5 x1 + x5 N˚ a er det enkelt ˚ a se at P ikke er regulær da det ikke finnes en entydig likevektsvektor.
https://www.pdf-archive.com/2015/09/16/mat1120-linear-algebra/
16/09/2015 www.pdf-archive.com