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### TDII - MDM (v2)100%

The moment distribution method essentially involves four steps to find the end moments of all members:

https://www.pdf-archive.com/2012/10/18/tdii-mdm-v2/

18/10/2012 www.pdf-archive.com

### micromoments-guide-to-winning-shift-to-mobile-summary97%

At a Glance Micro-Moments:

https://www.pdf-archive.com/2016/10/28/micromoments-guide-to-winning-shift-to-mobile-summary/

28/10/2016 www.pdf-archive.com

### Panel 196%

1hr       Self weight of slab m m mm 2 N/mm 3.6 KN/m 2 1.2 KN/m 2 1 KN/m 2  cover Fire resistance OK 5.8 KN/m2 gk 3 KN/m2 qk 12.92 Design load [1.4gk +1.6qk] DESIGN MOMENTS AND REINFORCEMENTS 1.659 Aspect ratio of slab SHORT SPAN [SUPPORT] 0.084 Support moment coefficient 10.738 Support moment 124 Effective depth of beam , [d] M 0.0279 K bd2 fcu 0.95 Lever arm, z, 117.80 KN/m2    n 20 mm 2 5.8 KN/m 2 3 KN/m 2 12.92 KN/m  Table 3.14 Table 3.14 3.4.4.4 3.4.4.4 3.4.4.4         Area of steel required, As   Minimum reinforcement area SHORT SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 BS8110 REF Table 3.14 Table 3.14 K  [d] M bd2 fcu Lever arm, z, Area of steel required, LONG SPAN [SUPPORT] Support moment coefficient Support moment Effective depth of beam , As         KNm mm d mm M 0.95 f y z 234 mm 2 195 mm2 [d] Y 12 at 250  2 453 mm 0.063 8.046 KNm 124 mm 0.0209 0.95 d 117.80 mm M 0.95 f y z 175 mm 2 Provide  CALCULATIONS    Provide 0.045 5.769 KNm 112 mm Y 12 OUTPUT at 300 2 377 mm 3.4.4.4 3.4.4.4 3.4.4.4 K  M bd2 fcu Lever arm, z, As Area of steel required, LONG SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, Area of steel required, As     0.0184 0.95 d 106.40 mm M 0.95 f y z   139 mm        2 Provide Y 12 at 300 Provide Y 12 2 377 mm 0.034 4.359 KNm 112 mm 0.0139 0.95 d 106.40 mm M 0.95 f y z  105 mm 2 377 at 300 mm2 2 377 mm BS8110 REF Table 3.9 DEFLECTION CHECK CALCULATIONS  Basic minimum effective depth for short span Moment redistribution factor   Tension reinforcement area required Table 3.10 Modification factor 3.12.11.2.7 Modified minimum effective depth CRACKING Cracking is controlled by limiting bar spacing.

https://www.pdf-archive.com/2017/06/11/panel-1/

11/06/2017 www.pdf-archive.com

### Panel 396%

1hr  Self weight of slab Partitions [minimum] Characteristic imposed load   Design load [1.4gk +1.6qk]  Characteristic dead load  cover Fire resistance OK 20 mm 3.6 KN/m2   Finishes 3.2.1.2.2 6.23 m 5.23 m 150 mm 2 25 N/mm 1.2 KN/m2 1 KN/m2 5.8 KN/m2 gk 3 KN/m2 qk 12.92 KN/m2  2 5.8 KN/m   n 2 3 KN/m 2 12.92 KN/m DESIGN MOMENTS AND REINFORCEMENTS 1.191 Aspect ratio of slab          SHORT SPAN [SUPPORT] Table 3.14 Table 3.14 Support moment coefficient Support moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, As Area of steel required, 0.0508 0.94 d 116.55 mm M 0.95 f y z 430 mm2 Provide Y12 at  195 mm2 Minimum reinforcement area BS8110 REF 0.055 19.540 KNm 124 mm CALCULATIONS 200 2 566 mm OUTPUT SHORT SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Support moment Effective depth of beam , 3.4.4.4 K 3.4.4.4 3.4.4.4  [d] M bd2 fcu Lever arm, z, Area of steel required, As                 0.041 14.632 KNm 124 mm 0.0381 0.95 d 117.80 mm M 0.95 f y z 319 mm2 Provide Y 12 at 250 2 453 mm  BS8110 REFthis PDF from an application thatCALCULATIONS OUTPUT You created is not licensed to print to novaPDF printer (http://www.novapdf.com) LONG SPAN [SUPPORT] Table 3.14 Table 3.14 Support moment coefficient Support moment Effective depth of beam , 3.4.4.4 K 3.4.4.4 3.4.4.4  Lever arm, z, [d] M bd2 fcu Area of steel required, As       0.037 13.051 KNm 112 mm  0.0416 0.95 d 106.40 mm M 0.95 f y z  315 mm2 Provide Y12 at Provide Y12 250 2 453 mm LONG SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Support moment Effective depth of beam , 3.4.4.4 K 3.4.4.4 3.4.4.4 Lever arm, z,  [d] M bd2 fcu Area of steel required, As        0.028 9.876 KNm 112 mm 0.0315 0.95 d 106.40 mm M 0.95 f y z  238 mm2 at 300 2 377 mm DEFLECTION CHECK Table 3.9 Basic minimum effective depth for short span Moment redistribution factor    Tension reinforcement area provided Tension reinforcement area required Design service stress 201.0 mm 1.0   fs  Table 3.10 Modification factor 3.12.11.2.7 Modified minimum effective depth CRACKING Cracking is controlled by limiting bar spacing.

https://www.pdf-archive.com/2017/06/11/panel-3/

11/06/2017 www.pdf-archive.com

### Panel 496%

1hr       Self weight of slab Finishes Partitions [minimum] Characteristic dead load Characteristic imposed load 3.2.1.2.2 3.15 m 2.23 m 150 mm 2 25 N/mm 3.6 KN/m  cover Fire resistance OK 20 mm 2 1.2 KN/m2 1 KN/m 2 2 5.8 KN/m 3 KN/m2 12.92 Design load [1.4gk +1.6qk] DESIGN MOMENTS AND REINFORCEMENTS 1.416 Aspect ratio of slab SHORT SPAN [SUPPORT] 0.075 Support moment coefficient 4.773 Support moment 124 Effective depth of beam , [d] M 0.0124 K bd2 fcu 0.95 Lever arm, z, 117.80 M Area of steel required, As 0.95 f y z KN/m2    gk qk n 2 5.8 KN/m 2 3 KN/m 2 12.92 KN/m  Table 3.14 Table 3.14 3.4.4.4 3.4.4.4 3.4.4.4         Minimum reinforcement area SHORT SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, Area of steel required, As KNm mm d mm   104 mm2        0.056 3.558 KNm 124 mm  195 mm Provide Y 12 at 300  2 2 377 mm 0.0093 0.95 d 117.80 mm M 0.95 f y z 78 mm2 Provide Y 12 at 300 2 377 mm  BS8110 REF CALCULATIONS OUTPUT LONG SPAN [SUPPORT]  0.045 Table 3.14 Support moment coefficient 2.878 KNm Table 3.14 Support moment You created this PDF from an application that is not licensed to print to novaPDF printer (http://www.novapdf.com)  Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, As Area of steel required,       112 mm 0.0092 0.95 d 106.40 mm M 0.95 f y z   69 mm2 Provide Y 12 at 300 377 mm 2 LONG SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, Area of steel required, As        0.034 2.175 KNm 112 mm 0.0069 0.95 d 106.40 mm M 0.95 f y z  Provide 52 mm2 Y 12 at 300 mm 377 2 2 377 mm BS8110 REF CALCULATIONS OUTPUT DEFLECTION CHECK Table 3.9 Basic minimum effective depth for short span Moment redistribution factor     Tension reinforcement area provided Tension reinforcement area required Design service stress 85.6 mm 1.0 fs  377 mm 78 mm2 2 f y Asreq  Table 3.10 Modification factor 3.12.11.2.7 Modified minimum effective depth CRACKING Cracking is controlled by limiting bar spacing.

https://www.pdf-archive.com/2017/06/11/panel-4/

11/06/2017 www.pdf-archive.com

### Panel 695%

1hr LOADING ON SLAB 3.2.1.2.2     3.6 KN/m2 Self weight of slab 1.2 KN/m2 Finishes 1 KN/m2 Partitions [minimum] 5.8 KN/m2 gk Characteristic dead load 3 KN/m2 qk Characteristic imposed load 12.92 KN/m2 n Design load [1.4g k +1.6qk] DESIGN MOMENTS AND REINFORCEMENTS 1.357 Aspect ratio of slab 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, Area of steel required, As Minimum reinforcement area         BS8110 REF CALCULATIONS LONG SPAN [SUPPORT] Table 3.14 Table 3.14 Support moment coefficient Support moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4 K  [d] M bd2 fcu Lever arm, z, Area of steel required, 2 5.8 KN/m 2 3 KN/m 2 12.92 KN/m  Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4      SHORT SPAN [MIDSPAN] Table 3.14 Table 3.14  cover 20 mm Fire resistance OK As         0.069 8.574 KNm 124 mm 0.0279 0.95 d 117.80 mm M 0.95 fy z 187 mm2 195 mm2 Provide Y12  OUTPUT 0.045 5.632 KNm 112 mm 0.0225 0.95 d 106.40 mm M 0.95 fy z at 250 2 453 mm Area of steel required,    As LONG SPAN [MIDSPAN] Table 3.14 Table 3.14 Midspan moment coefficient Midspan moment Effective depth of beam , 3.4.4.4 3.4.4.4 3.4.4.4  K Lever arm, z, Area of steel required, As BS8110 REF DEFLECTION CHECK Table 3.9 [d] M bd2 fcu M 0.95 fy z 136 mm2        CALCULATIONS 0.95 d 106.40 mm M 0.95 f y z 103 mm2     y sreq sprov  Table 3.10 Modification factor  0.55 Y 12 (477  fs )  2.0 M ) 2 bd 300 mm2 119.7 mm 1.0 453 mm2 187 mm2 * 1 b  2.00 59.86 mm  124 mm Cracking is controlled by limiting bar spacing.

https://www.pdf-archive.com/2017/06/11/panel-6/

11/06/2017 www.pdf-archive.com

26/06/2015 www.pdf-archive.com

### Flexible Parallel Robots, IEEE91%

if the legs are roughly parallel (i.e., at curvatures close to zero) the point force applied by each leg to the robot platform induces approximately constant moments in the other legs.

https://www.pdf-archive.com/2013/11/27/flexible-parallel-robots-ieee/

27/11/2013 www.pdf-archive.com

### MusicAndMemories90%

Flashbulb memories are specific moments in your life when you learned or heard something very significant.

https://www.pdf-archive.com/2011/03/29/musicandmemories/

29/03/2011 www.pdf-archive.com

### The insta-gratitude mindset90%

Some of you have become super clever at using social media to build a brand or an empire, some of you are using it to tell a story, to capture happy moments and some of you think it is all just a bit weird.

https://www.pdf-archive.com/2017/05/11/the-insta-gratitude-mindset/

11/05/2017 www.pdf-archive.com

### Mosty Obliczenia 24maja90%

https://www.pdf-archive.com/2018/05/24/mostyobliczenia24maja/

24/05/2018 www.pdf-archive.com

### QUANTUM MECHANICAL SPIN Krista Khiangte89%

https://www.pdf-archive.com/2020/02/01/quantum-mechanical-spinkrista-khiangte/

01/02/2020 www.pdf-archive.com

### Getting in the Present Moment - Clippings 201588%

https://www.pdf-archive.com/2016/06/05/getting-in-the-present-moment-clippings-2015/

05/06/2016 www.pdf-archive.com

### review-graphene-magnet88%

In nature, magnetic moments are carried by magnetic minerals the most common of which are magnetite and hematite.1, 15, 17, 18 The magnetic moment in practice may depend on the detailed environment and additional interactions such as spin-orbit, screening effects and crystal fields.

https://www.pdf-archive.com/2013/10/24/review-graphene-magnet/

24/10/2013 www.pdf-archive.com

### Scan Doc000687%

&gt;

https://www.pdf-archive.com/2015/02/17/scan-doc0006/

17/02/2015 www.pdf-archive.com

### Formelsammlung TM87%

https://www.pdf-archive.com/2012/01/25/formelsammlung-tm/

25/01/2012 www.pdf-archive.com

### El nino Score86%

The “storyline” is built on the general idea of destruction, that is present throughout the textural and rhythmic moments.

https://www.pdf-archive.com/2016/01/23/el-nino-score/

23/01/2016 www.pdf-archive.com

### Booklet86%

1 stonemilker 2 lionsong 3 history of touches 4 black lake 5 family 6 notget 7 atom dance 8 mouth mantra 9 quicksand show me emotional respect i have emotional needs i wish to synchronize our feelings 1 stonemilker a juxtapositioning fate find our mutual coordinate what is it that i have that makes me feel your pain like milking a stone to get you to say it 9 months before moments of clarity are so rare i better document this at last the view is fierce all that matters is who is open and who has shut up and if one feels closed how does one stay open who is open chested and who has coagulated who can share and who has shut down the chances we have emotional needs i wish to synchronize our feelings show some emotional respect once it was simple one feeling at a time it reached it’s peak then transformed these abstract complex feelings i just don’t know how to handle them should i throw oil on one of his moods but which one make the joy peak humour peak frustration peak anything peak for clarity 2 lionsong 5 months before maybe he will come out of this maybe he won’t somehow i’m not too bothered either way maybe he will come out of this loving me maybe he will come out of this i smell declarations of solitude maybe he will come out of this maybe he will come out of this loving me maybe he won’t i’m not taming no animal maybe he will come out of this vietnam vet comes after the war lands in my house this wild lion doesn’t fit in this chair maybe he will come out of this maybe he won’t somehow i’m not too bothered either way maybe he will come out of this loving me maybe he won’t i’m not taming no animal maybe he will come out of this i refuse it’s sign of maturity to be stuck in complexity i demand clarity either way maybe he will come out of this somehow i’m not too bothered i’d just like to know 3 history of touches i wake you up in night feeling this is our last time together therefore sensing all the moments we’ve been together being here at the same time every single touch we ever touch each other every single fuck we had together is in a wondrous time lapse with us here at this moment the history touches every single archive compressed into a second all with us here as i wake you up 3 months before i wake you up in the middle of the night to express my love for you stroke your skin and feel you naked i can feel all of you at same moment

https://www.pdf-archive.com/2015/01/21/booklet/

21/01/2015 www.pdf-archive.com

### Diss V Schwachmeyer85%

The implants measure in vivo the forces and moments in 3 planes.

https://www.pdf-archive.com/2016/11/15/diss-v-schwachmeyer/

15/11/2016 www.pdf-archive.com

### An Unreliable Witness Read 5555cefb22b52-285%

Alice May Williams An Unreliable Witness KEY:

16/11/2015 www.pdf-archive.com

### TFTW 02-25-201685%

FALLOUT NUKA BREAK:

https://www.pdf-archive.com/2016/09/04/tftw-02-25-2016/

04/09/2016 www.pdf-archive.com

### blackbird84%

https://www.pdf-archive.com/2019/11/11/blackbird/

11/11/2019 www.pdf-archive.com

### info booklet84%

https://www.pdf-archive.com/2013/05/18/info-booklet/

18/05/2013 www.pdf-archive.com

### Mathcad - Lab7 - Derivation84%

h ho x a F1 F2 L Find MOR Solving Reactions F1 , F2 Sum of moments about roller connection therefore F1 ⋅ L = F⋅ a Sum of forces in the y direction F⋅ a therefore + F2 − F = 0 L F⋅ a Fa = L F⋅ a a F2 = F − = F⋅  1 −  L L   Shear (Top) and Moment Diagram (Bottom) Fa/L (Fa(L-a)/L) Moment is simply integral of Shear M peak = F⋅ a L ⋅ ( L − a) F(1-a/L) Now Solve M(x), moment as a function of x M 1 ( x) = m⋅ x + b Note, b here is the intercept b =0 m= M 1 ( x) = F⋅ a L F⋅ a L FOR 0 &lt;