Rangkuman trigonometri bagian 1 .pdf

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KESIMPULAN

Rangkuman SUDUT BERELASI
sin(90 0   )  cos 
sin(1800   )  sin 

sin( 180 0   )   sin x

0

cos( 900   )   sin 

0

cos(180   )   cos 

cos(180   )   cos 

tan(1800   )   tan 

tan(180 0   )  tan 

tan(900   )   cot 
1
   )  cos 
2
1
cos(    )  sin 
2
1
tan(    )  cot 
2

sin(

sin(    )   sin 
cos(   )   cos 

sin(   )  sin 

tan(    )  tan 

cos(   )   cos 
tan(   )   tan 

0

sin(360   )   sin 
0

cos( 360   )  cos 

sin   cos( 90 0   )

sin(2700   )   cos 

cos   sin( 90 0   )

cos( 2700   )   sin 

0

tan(360   )   tan x
sin( 2    )   sin 
cos( 2    )  cos 
tan( 2    )   tan 

sin     sin 

sin(  k .3600 )  sin 

cos    cos 
tan     tan 

cos(  k .360 0 )  cos 
tan(  k .360 0 )  tan 

1800  
3600  

Kesimpulan ::1. fungsi trigonometri

2. fungsi trigonometri

tan( 2700   )   cot 

tan   cot( 90   )
1
sin(    )  cos 
2
1
cos(    )  sin 
2
1
tan(    )  cot 
2

0

90 0 
270 0 

3
sin(    )   cos 
2
3
cos(    )  sin 
2
3
tan(    )   cot 
2

sin(  k .2 )  sin 
cos(  k .2 )  cos 
tan(  k .2 )  tan 

nama tetap
tanda sesuai kuadran
nama berubah
tanda sesuai kuadran

Contoh Soal :
Tentukan nilai : a. sin 2250 , b. sin 1200
Jawab :
a. sin 225 0  sin(180 0  45 0 )   sin 45 0   2
2

| b. sin 120 0  sin(180 0  60 0 )   sin 60 0   3
2
TUGAS!!

Kerjakan soal-soal berikut ini pada buku tugas kalian, kumpulkan!
Ubah perbandingan trigonometri ini menjadi perbandingan trigonometri sudut lancip ,hitung
Tentukan nilai dari :
(soal no 6 – 10):
1. cos 240
4. tan 135 
0

2.

cos 150 

5. tan 300 

7. cos 240

3.

sin 300 

6. tan 120 0

8. cos -135 0

9. sin -45 0
10. tan 390 0


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