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» Lycée Agoune Mohand El Yazid Ighil-Ali « Bejaia
3 eme maths
Composition du
1er trimestre
ﺗﻤﺮﻳﻦ 1
ﻳﺘﻮﻓﺮ ﻃﺒﻴﺐ اﻷﻣﺮاض اﻟﻌﺼﺒﻴﺔ ﻋﻠﻰ ﺗﻘﻨﻴﺎت ﻣﺨﺘﻠﻔﺔ ﻟﺘﺸﺨﻴﺺ ﺣﺎﻟﺔ اﺷﺘﻐﺎل دﻣﺎغ اﻹﻧﺴﺎن و ﻣﻦ ﺑﻴﻦ هﺬﻩ
اﻟﺘﻘﻨﻴﺎت ،ﺗﻘﻨﻴﺔ (topographie par émission de positron )PEPو اﻟﺘﻲ ﺗﻌﻄﻲ ﺗﻐﻴﺮ ﺗﺪﻓﻖ اﻟﺪم و ﺑﺎﻟﺘﺎﻟﻲ ﻧﺸﺎط
اﻟﺪﻣﺎغ .ﺗﻘﻨﻴﺔ TEPﺗﺤﺪد ﺟﺰﻳﺌﺎت اﻟﻤﺎء اﻟﻤﻮﺟﻮدة ﻓﻲ دﻣﺎغ اﻹﻧﺴﺎن وذاﻟﻚ ﺑﺎﺳﺘﻌﻤﺎل اﻟﻤﺎء اﻟﻤﺸﻴﻊ اﻟﺬي
ﻳﺤﺘﻮي ﻋﻠﻰ اﻷآﺴﺠﻴﻦ
βو اﻟﺬي ﻳﺤﻘﻦ ﻓﻲ دم اﻹﻧﺴﺎن ﻋﻦ ﻃﺮﻳﻖ اﻷوﻋﻴﺔ .
اﻟﺒﺎﻋﺚ ﻟﻠﺪﻗﺎﺋﻖ
زﻣﻦ ﻧﺼﻒ ﻋﻤﺮ
1ـ اآﺘﺐ ﻣﻌﺎدﻟﺔ ﺗﻔﻜﻚ ﻧﻮاة اﻷآﺴﺠﻴﻦ
هﻮ
123
/
ﻋﻠﻤﺎ أن اﻟﻨﻮاة اﻟﻨﺎﺗﺠﺔ هﻲ
2ـﺄﺣﺴﺐ اﻟﻄﺎﻗﺔ Eاﻟﻤﺘﺤﺮرة ﺑـ MeVإﺛﺮ ﺗﻔﻜﻚ ﻧﻮاة ﻣﻦ
3ـ ﺑﻴﻦ أن ﻋﺒﺎرة اﻟﻄﺎﻗﺔ ETو اﻟﻨﺎﺗﺠﺔ ﻋﻦ ﺗﻔﻜﻚ
/
1
ﺗﻜﺘﺐ وﻓﻖ ﻣﺎ ﻳﻠﻲ:
4ـ ﻟﺘﻜﻦ 2
ﻣﻦ أﻧﻮﻳﺔ اﻷآﺴﺠﻴﻦ ﻋﻨﺪ اﻟﻠﺤﻈﺔ
/
آﺘﻠﺔ اﻷآﺴﺠﻴﻦ 15اﻟﺘﻲ ﺗﻢ ﺣﻘﻨﻬﺎ ﻓﻲ اﻟﻠﺤﻈﺔ t=0sﻟﻤﺮﻳﺾ .أﺛﺒﺖ أن ﺛﺎﺑﺖ اﻟﻨﺸﺎط
ﻣﻌﻄﻰ ﺑﺎﻟﻌﺒﺎرة اﻟﺘﺎﻟﻴﺔ :
/
λ
3
5ـ ﻋﻴﻦ ﻋﺪد اﻷﻧﻮﻳﺔ اﻟﻤﺘﻔﻜﻜﺔ ﺑﻌﺪ ﻣﺮور
6ـ أﺣﺴﺐ آﺘﻠﺔ أﻧﻮﻳﺔ اﻷآﺴﺠﻴﻦ اﻟﻤﺘﻔﻜﻜﺔ.
7ـ ﻟﺘﻜﻦ
ﻋﺪد أﻧﻮﻳﺔ اﻷآﺴﺠﻴﻦ اﻟﻤﺘﻔﻜﻜﺔ و
1
ﻋﺪد أﻧﻮﻳﺔ اﻷآﺴﺠﻴﻦ اﻟﻤﺘﺒﻘﻴﺔ ﻋﻨﺪ اﻟﻠﺤﻈﺔ
.ﺑﻴﻦ أن:
e
ﺗﻤﺮﻳﻦ2
اﻟﺘﻮﻟﻮﻳﻦ هﻮ ﺳﺎﺋﻞ ﻋﺪﻳﻢ اﻟﻠﻮن ﻳﻨﺘﻤﻲ إﻟﻰ ﻋﺎﺋﻠﺔ اﻟﻔﺤﻮم اﻟﻬﻴﺪروﺟﻴﻨﻴﺔ ﻳﺴﺘﻌﻤﻞ ﻓﻲ اﻟﻌﻄﻮر و آﺬا ﺻﻨﺎﻋﺔ
اﻟﻤﺘﻔﺠﺮات ) .( TNT
ﻧﻤﺰج آﻤﻴﺔ n0ﻣﻦ ﺛﻨﺎﺋﻲ اﻟﻜﻠﻮر
ﺑﻄﻲء وﻓﻖ ﻣﺎ ﻳﻠﻲ :
ﻣﻊ آﻤﻴﺔ واﻓﺮة ) ﻳﻌﻨﻲ ﺑﻮﻓﺮة( ﻣﻦ اﻟﺘﻮﻟﻮﻳﻦ
ﻓﻴﺤﺪث ﺗﻔﺎﻋﻞ
Droits réservés : bracadabra70@hotmail.com
» Lycée Agoune Mohand El Yazid Ighil-Ali « Bejaia
3 eme maths
ﺗﻤﻜﻨﺖ اﻟﻤﺘﺎﺑﻌﺔ اﻟﺰﻣﻨﻴﺔ ﻟﺘﻐﻴﺮات ﺗﺮآﻴﺰ ﺛﻨﺎﺋﻲ اﻟﻜﻠﻮر ﻓﻲ ﺣﺠﻢ
Composition du
1er trimestre
V=200mlﺑﺎﻟﺤﺼﻮل ﻋﻠﻰ اﻟﻤﻨﺤﻨﻰ اﻟﺒﻴﺎﻧﻲ
) اﻟﻮﺛﻴﻘﺔ ( 1
1ـ ﺷﻜﻞ ﺟﺪول اﻟﺘﻘﺪم ﻟﻬﺬا اﻟﺘﺤﻮل .
2ـ أوﺟﺪ ﻋﺒﺎرة ﺗﻘﺪم اﻟﺘﻔﺎﻋﻞ ) x(tﺑﺪﻻﻟﺔ n0و
،
3ـ ﻋﻴﻦ آﻤﻴﺔ اﻟﻤﺎدة ﻟﻜﻞ ﻣﻦ ،
] [Cl2ﺗﺮآﻴﺰ ﺛﻨﺎﺋﻲ اﻟﻜﻠﻮر ﻋﻨﺪ ﻟﺤﻈﺔ tو Vﺣﺠﻢ اﻟﺨﻠﻴﻂ.
،
ﻋﻨﺪ اﻟﻠﺤﻈﺔ
600
4ـ ﻋﺒﺮ ﻋﻦ اﻟﺴﺮﻋﺔ اﻟﺤﺠﻤﻴﺔ ﻟﻬﺬا اﻟﺘﺤﻮل ﺑﺪﻻﻟﺔ ][Cl2
5ـ أﺣﺴﺐ ﻗﻴﻤﺔ هﺬﻩ اﻟﺴﺮﻋﺔ ﻋﻨﺪ اﻟﻠﺤﻈﺔ
800
6ـ ﻋﻨﺪ رﻓﻊ درﺟﺔ ﺣﺮارة اﻟﻮﺳﻂ اﻟﺘﻔﺎﻋﻠﻲ ﺗﻜﻮن ﻗﻴﻤﺔ ﺗﺮآﻴﺰ ][Cl2ﻋﻨﺪ t = 800mnأﺻﻐﺮ ﻣﻦ
. 0,137 mol/Lآﻴﻒ ﻳﻤﻜﻦ ﺗﻔﺴﻴﺮ ذاﻟﻚ .
7ـ ﺑﻴﻦ أﻧﻪ ﻣﻦ أﺟﻞ اﻟﻠﺤﻈﺔ
/
) زﻣﻦ ﻧﺼﻒ اﻟﺘﻔﺎﻋﻞ (
/
ِ
ﻋﻴﻦ ﻓﻲ هﺪﻩ اﻟﺨﺎﻟﺔ زﻣﻦ ﻧﺼﻒ اﻟﺘﻔﺎﻋﻞ ﻣﻦ اﻟﺒﻴﺎن.
ﺗﻤﺮﻳﻦ 3
اﻟﺒﺴﻤﻮت
هﻮ ﺑﺎﻋﺚ ﻟﻠﺠﺴﻴﻤﺎت . αاﻟﻨﻮاة اﻻﺑﻦ هﻲ ﻧﻀﻴﺮ ﻟﻌﻨﺼﺮ اﻟﺘﺎﻟﻴﻮم
.
ﻳﻤﻜﻦ ﻟﻨﻮاة اﻻﺑﻦ
أن ﺗﺼﺪر أو ﻻ إﺷﻌﺎع آﻬﺮوﻣﻐﻨﺎﻃﻴﺴﻲ.
1ـ أآﺘﺐ ﻣﻌﺎدﻟﺔ اﻟﺘﻔﻜﻚ اﻟﺘﻠﻘﺎﺋﻲ ﻣﻌﻴﻨﺎ Zو َ ﻣﺒﻴﻨﺎ اﻟﻄﺮﻳﻘﺔ اﻟﻤﺴﺘﻌﻤﻠﺔ
2ـ ﻋﻴﻦ ﻗﻴﻤﺔ اﻟﻄﺎﻗﺔ اﻟﻤﺘﺤﺮرة ﻣﻦ ﺗﻔﻜﻚ ﻧﻮاة واﺣﺪة ﻣﻦ اﻟﺒﺴﻤﻮت .
3ـ ﻟﻠﺒﺴﻤﻮت ﻧﻤﻄﻴﻦ ﻣﻦ اﻟﺘﻔﻜﻚ.
Íأﺛﻨﺎء اﻟﺘﻔﻜﻚ ﻻ ﻳﻨﺒﻌﺚ إﺷﻌﺎع آﻬﺮو ﻣﻐﻨﺎﻃﻴﺴﻲ .γﻟﻠﻨﻮاة اﻻﺑﻦ ﺳﺮﻋﺔ ﻣﻌﺪوﻣﺔ .أﺣﺴﺐ ﻣﻘﺪار اﻟﻄﺎﻗﺔ
اﻟﺤﺮآﻴﺔ ﻟﻠﺠﺴﻴﻤﺔ α
Íأﺛﻨﺎء اﻟﺘﻔﻜﻚ ﻳﻨﺒﻌﺚ إﺷﻌﺎع آﻬﺮو ﻣﻐﻨﺎﻃﻴﺴﻲ γﺑﻄﺎﻗﺔ ﻗﺪرهﺎ . 0,47MeVاﺣﺴﺐ ﻓﻲ هﺬﻩ اﻟﺤﺎﻟﺔ
ﻗﻴﻤﺔ اﻟﻄﺎﻗﺔ اﻟﺤﺮآﻴﺔ ﻟﻠﺠﺴﻴﻤﺔ α
Droits réservés : bracadabra70@hotmail.com
Co
ompositio
on du
1er trimestre
0,4
Lycée
e Agoune
e Mohand El Yazid Ighil-Ali « Bejaia
a»
e
3 eme
math
hs
[Cl2](mol/L
]
0,35
ﻋﻨﺪ
اﻟﻤﻤﺎس ﻋ
0,3
t = 800 mn
0,25
0,2
0,15
0,1
0,05
t(mn)
0
0
20
00
400
600
8
800
1000
Droits réservé
és : bra
acadabrra70@hotmail.c
com
1200
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