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Temp.pdf

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We wish to solve aR Z 2 a f .ar/ D 2f .r/ f .u/u du () 0 for the function f . As per the recommendation in the paper, we differentiate with respect to a,  .?/ d    d d  2 a  f .ar/ D a2 f .ar/ C a2 f .ar/ D 2af .ar/ C a2 rf 0 .ar/ da da da 0 The equality (?) follows from the product rule: fg D f 0 g C fg 0 . Next, we apply the same operation to the RHS of equation ./. ! ! Z aR Z aR d d 2f .r/ f .u/u du D 2f .r/ f .u/u du da da 0 0 ! Z aR aR d  .01/ D 2f .r/ uF .u/ 0 F .u/ du da 0 ! Z aR d D 2f .r/ aRF .aR/ F .u/ du da 0 ! Z aR   d .?/ 2 0 F .u/ du D 2f .r/ aRF .aR/ C aR F .aR/ da 0   .02/ D 2f .r/ aRF .aR/ aR2 f .aR/ C RF .aR/   D 2f .r/ RF .aR/ .1 a/ C aR2 f .aR/ a/f .r/F .aR/ C 2aR2 f .r/f .aR/ R R 0 (01) is determined by utilizing integration by parts: fg 0 D fg f g. (02) follows from evaluating the R aR Rx d d quantity da 0 F .u/ du by implementing the fundamental theorem of calculus: f .x/ D dx c f .t / dt . (?) is another application of the product rule. Combining these results, we have D 2R.1 2af .ar/ C a2 rf 0 .ar/ D 2R.1 a/f .r/F .aR/ C 2aR2 f .r/f .aR/: As specified, substitute a D 1, to obtain 2f .r/ C rf 0 .r/ D 2R2 f .r/f .R/ This is a differential equation in variable r with dependent variable f . We can recognize that this is a first-order linear ordinary differential equation. f .R/ is just a constant, so we write this as f .R/ D rR . We are solving 2 2rR R2 f0C f D0 r for f . The solution is, trivially, f .r/ D C e R .2 2rR R2 /=r dr D C e .2rR R 2 2/ lnjrj 03 .2rR R2 04 2 D C e ln.r D C r 2rR R D C rq 2 : 2/ / 2 (q D 2rR R2 ) Notice that 0  r  1, so the absolute function becomes redundant on r. (03) follows from the log law x log y D log y x . (04) follows from the log law e ln x D x. 1 of 2 To find C , we use suggestion that f .r/ must satisfy the normalization condition (3). Z 2 R Z f .r/r dr d# D 1 0 (3) 0 That is, Z 2 Z R Z 0 2 Z R C rq 1D 0 DC 0 rq r dr d# 1 dr d# 0 2 Z 2 DC 0  1 q r q R d# 0 Z 2 1 d# D C Rq q 0 1 D C Rq 2 q Solving for C , ,C D q : 2Rq Therefore, f .r/ D qr q 2 : 2Rq 2 of 2 

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Temp.pdf
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